NTA Tie Breaking Formula For JEE Mains: National Testing Agency has released the results of JEE Mains exam 2024. This time a total of 56 students have got 100 percentile. Neelkrishna of Maharashtra has topped. Sanjay Mishra and Aarav Bhatt stood second and third respectively. Aditya Kumar stood fourth and Hundekar Vidit stood fifth. In such a situation, if this question also comes in your mind that when 56 students have got 100 percentile then how was the topper decided, then we answer it.
NTA made rules
NTA has made many rules for tie breaking on the basis of which the rank is decided. Many students know how first, second and third ranks are given when they get the same percentile. Before proceeding further, know why NTA had to make these rules. In the year 2021, a total of 18 students got AIR 1. Then the agency decided that there should be only one topper and set some rules for it.
These two aspects are considered first
There are many points to decide the topper but the first two aspects which are considered are age and application number. The candidate who is older and who filled the form first is given preference. It rarely happens that two candidates are of the same age and have applied at the same time.
This is also seen
If the rank is not decided even on this issue, then the marks of Maths are considered. If this is also the same, then first the marks of Physics and then of Chemistry are considered. If this still doesn’t work, then the ratio of how many correct and how many wrong answers a candidate has given is seen. This ratio is seen mostly in Maths subject, then in Physics and then in Chemistry. Overall, the topper is decided by considering these points.
How to calculate percentile
The session in which the candidate has attended to remove it. The total number of all the candidates present in it who have scored equal or less marks has to be multiplied by 100. This is calculated up to seven decimals. It is calculated on a scale of 100 to 0.
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